Debug
输入sql语句，但不执行
debug()
Return: 开启Medoo调试模式
输出sql语句，不需要使用echo或其它方法。调试完成请移除此代码
$database->debug()->select("bccount", [
"user_name",
"email"
], [
"user_id[<]" => 20
]);
// Will output:
// SELECT "user_name","email" FROM "bccount" WHERE "user_id" < 20
// [Multiple situation]
// Output nothing
$database->insert("account", [
"user_name" => "foo",
"email" => "[email protected]"
]);
// Will output the generated query
$post_id = $database->debug()->get("post", "post_id", ["user_name" => "foo"]);
// Be careful, this query will be executed.
$database->update("account", [
"level[+]" => 5,
"post" => $post_id
], [
"user_name" => "foo"
]);